Momentum and CollisionHard

Question

A particle of mass m moving in the x direction with speed 2υis hit by another particle of mass 2m moving in the y direction with speed υ. If the collisions perfectly inelastic , the percentage loss in the energy during the collision is close to :

Options

A.56 %
B.62 %
C.44 %
D.50 %

Solution

   
Kinetic energy = m(2v)2 × 2m(v)2
= 3 mv2
After collison
Applying momentum conservation for inelastic collision
2mvĵ + m2vî = 3m

Kf = × 3m × (vf2) =
% ᐃK = = 56%

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