Current Electricity and Electrical InstrumentHard
Question
An inductor (L = 0.03 H) and a resistor (R = 0.15 kΩ) are connected in series to a battery of 15V EMF in a circuit shown below. The key K1 has been kept closed for a long time. Then at t = 0, K1 is opened and key K2 is closed simultaneously. At t = 1ms, the current in the circuit will be (e5 ≅ 150)
Options
A.6.7 mA
B.6.7 mA
C.0.67 mA
D.67 mA
Solution
Decay of current
I = I0e-tR/L
= 6.66 × 10-4
= 0.666 × 10-3
= 0.67 mA
I = I0e-tR/L
= 6.66 × 10-4
= 0.666 × 10-3
= 0.67 mA
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
In a balanced wheat stone bridge, current in the galvanometer is zero. It remains zero when...In the diagram shown, all the wires have resistance R. The equivalent resistance between the upper lower dots shown in t...In a potentiometer experiment a voltage source is balanced at 60cm length where as a 3 volt battery is balanced at 45cm ...Reading of ammeter in ampere for the following circuit is :-...A copper wire stretched so as to make it 0.1% longer. The percentage increase in the resistance of the wire is : -...