Principle of Inheritance and VariationHard
Question
The linkage map of X-chromosomes of fruit fily has 66 units, with yellow body gene (y) at one end and bobbed haie (b) sene at the other end. The recombination freqency between these two genes (y and b) should be
Options
A.≤ 50 %
B.100 %
C.66 %
D.≥ 50 %
Solution
The actual distance between two genes is said to be equivalent to the percentage of crossing over between these two genes. Since the two genes lie at the ends of the chromosome, there are 100% chances of their segregation during crossing over.
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