Principle of Inheritance and VariationMedium
Question
A woman with tow genes (one on each ′X′ chromosome) for haemophilia and one gene for colourblindness on the ′X′ chromosomes marries a normal man. How will the progeny be ?
Options
A.All sons and daughters haemophilic and colourblind
B.Haemophilic and colourblind daughters
C.50% haemophilic colourblind sons and 50% haemophilic sons
D.50% haemophilic daughters and 50% colourblind daughters
Solution
Haemophilia and colou rblindness both are recessive X- linked traits. They express in males when present in single copy (heterozygous) but in females they express only ehen present in heterozygous condition.
Results :
(a) 50% sons are colourblinds and haemophilic.
(b) 50% sons are haemophilic only
(c) 50% daughters are carrier for colour blindess and haemophilia.
(d) 50% daughters are carrier for haemophilia only.
Results :
(a) 50% sons are colourblinds and haemophilic.
(b) 50% sons are haemophilic only
(c) 50% daughters are carrier for colour blindess and haemophilia.
(d) 50% daughters are carrier for haemophilia only.
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