Trigonometric EquationHard

Question

The expression is equal to

Options

A.0
B.1
C.3
D.sin 4α + cos 6α

Solution



= 3(cos4α + sin4α) - 2(cos6α + sin6α)
= 3(1- 2sin2α cos2α) - 2(1-3sin2α cos2α)
= 3- 6sin2α cos2α - 2 + 6sin2α cos2α = 1

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