JEE Advanced | 2013Trigonometric EquationHard
Question
Given A = sin2 θ + cos4 θ then for all real values of θ
Options
A.1 ≤ A ≤ 2
B.
≤ A ≤ 1
≤ A ≤ 1C.
≤ A ≤ 1
≤ A ≤ 1D. ≤ A ≤
≤ A ≤ Solution
Given, Asin2 θ + (1 - sin2 θ)2
⇒ Asin4 θ - sin2 θ + 1
⇒
∵ 0 ≤ sin2 θ ≤ 1
⇒
∴
≤ A ≤ 1
⇒ Asin4 θ - sin2 θ + 1
⇒
∵ 0 ≤ sin2 θ ≤ 1
⇒
∴
≤ A ≤ 1Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
Locus of mid point of the portion between the axes of x cos α + y sin α = p where p is constant is...If α + β = and β + γ = α, then tan α equals...If sin x + sin2 x = 1, then cos12x + 3cos10 x + 3cos8x + cos6x - 2 is equals to -...Which of the following is/are correct -...If 2 tan2θ = sec2θ, then the general value of θ is -...