Redox and Equivalent ConceptEasy
Question
KMnO4 reacts with oxalic acid according to the equation
2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10 CO2 + 8 H2O
Here, 20 mL of 0.1 M KMnO4 is equivalent to :-
2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10 CO2 + 8 H2O
Here, 20 mL of 0.1 M KMnO4 is equivalent to :-
Options
A.120 mL of 0.25 M H2C2O4
B.150 mL of 0.10 M H2C2O4
C.25 mL of 0.20 M H2C2O4
D.50 mL of 0.20 M H2C2O4
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