KMnO4 reacts with oxalic acid according to the equation2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10 CO2 + 8 H2OHere, 20 mL of 0.1 M KMnO4 is equivalent to :-

Redox and Equivalent ConceptHard

Question

KMnO₄ reacts with oxalic acid according to the equation
2MnO₄^- + 5C₂O₄^2- + 16H⁺ → 2Mn²⁺ + 10 CO₂ + 8 H₂O
Here, 20 mL of 0.1 M KMnO₄ is equivalent to :-

Options

A.120 mL of 0.25 M H₂C₂O₄

B.150 mL of 0.10 M H₂C₂O₄

C.25 mL of 0.20 M H₂C₂O₄

D.50 mL of 0.20 M H₂C₂O₄

Solution

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