Laws of MotionHard
Question
Consider a 2 kg block B connected to block A through a string passing over a pulley as shown in figure. It is found that when the block A is 1 kg or more, the block B slides on table when the car is stationary. Now car starts moving with an acceleration on horizontal road. It is seen that now the block B moves on the table when block A is 1.2 kg or more. The acceleration of the car is
Options
A.3 m/s2
B.1 m/s2
C.2 m/s2
D.4 m/s2
Solution
μ2g = 1 × g ⇒ μ = 0.5
2μg + 2a = 1.2g ⇒ 2a = 0.2g ⇒ a = 1 m/s2
2μg + 2a = 1.2g ⇒ 2a = 0.2g ⇒ a = 1 m/s2
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