Let A & B be two independent events of an experiment such that B is twice as likely to occur as A. I

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Let A & B be two independent events of an experiment such that B is twice as likely to occur as A. If P(A) denotes the probability of occurence of A where P(A) &#8712; [a,b] then a + is equal to -

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Let P(A) = x&#8658; P(B) = 2xNow P(A &#8746; B) = P(A) + P(B) - P(A &#8745; B)= P(A) + P(B) - P(A).P(B) = x + 2x - 2x2Now 0 &#8804; P(A &#8746; B) &#8804; 1&#8658; 0 &#8804; 3x - 2x2 &#8804; 1&#8658; x &#8712; &#8658; a + = 4

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