Wave motionHard
Question
If y1 = 5 (mm) sinπt is equation of oscillation of source S1 and y2 = 5 (mm) sin(πt + π/6) be that of S2 and it takes 1 sec and 1/2 sec for the transverse waves to reach point A from sources S1 and S2 respectively then the resulting amplitude at point A, is
Options
A.
mm
mmB.5√3 mm
C.5 mm
D.5√2 mm
Solution
Wave originating at t = 0 from S1 reaches point A at t = 1.
Wave originating at t =
from S2 reaches point A at t = 1.
So phase difference in these waves =
A =
Wave originating at t =
from S2 reaches point A at t = 1.So phase difference in these waves =
A =
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