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Indefinite Integration
Hard
Question
is equal to-
Options
A.
tan−1 x −
tan−1 x / 2 + c
B.
tan−1 x −
tan−1 x / 2 + c
C.
tan−1 x +
tan−1 x / 2 + c
D.
tan−1 x − 2 tan−1 x / 2 + c
Solution
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Topic:
Indefinite Integration
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