Gauss LawEasy
Question
Eight point charges having magnitude q are fixed at vertices of a cube. The electric flux through square surface ABCD of the cube is
Options
A.
B.
C.
D.
Solution
By symmetry φ due of charge at E, F, G & H from face ABCD are equal Q due to charge at
E =
Q due to charge at E, F, G, M = 4 ×
Q due to charge at A, B, C & D = 0
field lines are perpendicular to area vector
E =
Q due to charge at E, F, G, M = 4 ×
Q due to charge at A, B, C & D = 0
field lines are perpendicular to area vector
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