CircleMedium
Question
The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle of area 154 sq unit. Then the equation of this is
Options
A.x2 + y2 + 2x - 2y = 62
B.x2 + y2 + 2x - 2y = 47
C.x2 + y2 - 2x + 2y = 47
D.x2 + y2 - 2x + 2y = 62
Solution
Since, 2x - 3y = 5 and 3x - 4 y = 7 are diameters of a circle.
Their point of intersection is centre (1, -1)
Also given, πr2 = 154
⇒ r2 = 154 ×
⇒ r = 7
∴ Required equation of circle is
(x -1)2 + (x + 1)2 = 72
⇒ x2 + y2 - 2x + 2y = 47
Their point of intersection is centre (1, -1)
Also given, πr2 = 154
⇒ r2 = 154 ×
⇒ r = 7∴ Required equation of circle is
(x -1)2 + (x + 1)2 = 72
⇒ x2 + y2 - 2x + 2y = 47
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