CircleHard
Question
The locus of the mid point of a chord of the circle x2 + y2 = 4 which subtends a right angle at the origin, is
Options
A.x + y = 2
B.x2 + y2 = 1
C.x2 + y2 = 2
D.x + y =1
Solution
We have to find locus of mid point of chord and we know perpendicular from centre bisects the chord.
∴ ∠OAC = 45o
In ᐃOAC,
= sin 45o ⇒ OC = 
Also,
= OC2 Hence, x2 + y2 = 2 is required equation of locus of locus of mid point of chord subtending right angle at the centre.Create a free account to view solution
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