Straight LineHard
Question
The incentre of the triangle with vertices (1, √3), (0,0) and (2,0) is
Options
A.
B.
C.
D.
Solution
Let the vertices of triangle be A(1√3), B(0,0) and C (2, 0),
Here, AB = BC = CA = 2
Therefore, it is an equilateral triangle. So the incentre coincides with centroid.
∴
⇒ (1,1/√3)
Here, AB = BC = CA = 2
Therefore, it is an equilateral triangle. So the incentre coincides with centroid.
∴
⇒ (1,1/√3)
Create a free account to view solution
View Solution FreeMore Straight Line Questions
The equation of the lines which passes throughthe point (3, −2) and are inclined at 60o to theline √3 x + y ...Let L be the line $\frac{x + 1}{2} = \frac{y + 1}{3} = \frac{z + 3}{6}$ and let S be the set of all points $(a,b,c)$ on ...If the sum of the slopes of the lines given by $x^2 - 2cxy - 7y^2 = 0$ is four times their product, then $c$ has the val...The angle between the lines represented by ax2 + 2hxy + by2 = 0 is -...The area of the triangle formed by the lines x = 0, y = 0 and x/a + y/b = 1 is -...