Straight LineMedium
Question
The diagonals of a parallelogram PQRS are along ther lines x + 3y = 4 and 6x - 2 y = 7. Then, PQRS must be a
Options
A.rectangle
B.square
C.cyclic quadrilateral
D.rhombus
Solution
Slope of line x + 3y = 4 is - 1/ 3
and slope of line 6x - 2 y = 7 is 3.
Here,
Therefore, these two lines are perpendicular which show that both diagonals are perpendicular.
Hence, PQRS must be a rhombus.
and slope of line 6x - 2 y = 7 is 3.
Here,
Therefore, these two lines are perpendicular which show that both diagonals are perpendicular.
Hence, PQRS must be a rhombus.
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