SemiconductorEasy
Question
In an n-p-n transistor (in common emitter mode) 1010 electrons enter the emitter in 10-6 sec. Only 2% of the electrons are lost in the base. Calculate the base current. Charge on electron is 1.6 × 10-19 C.
Options
A.0.032mA
B.0.32mA
C.3.2mA
D.32mA
Solution
Ie = 
= 1.6 × 10-3 A
Ib =
× 1.6 × 10-3 = 0.032 mA
= 1.6 × 10-3 AIb =
× 1.6 × 10-3 = 0.032 mACreate a free account to view solution
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