GravitationHard
Question
For a planet having mass equal to mass of the earth but radius is one fourth of radius of the earth, Then escape velocity for this planet will be :-
Options
A.11.2 km/sec.
B.22.4 km/sec.
C.22.4 m/s.
D.44.8 km/sec.
Solution
As Vesc ∝ 
= 2
Vplanet = 11.2 × 2 km/sec
= 22.4 km/sec
Vplanet = 11.2 × 2 km/sec
= 22.4 km/sec
Create a free account to view solution
View Solution FreeMore Gravitation Questions
Two concentric shells of masses M1 and M2 are having radii r1 and r2. Which of the following is the correct expression f...If the law of gravitation be such that the force of attraction between two particles vary inversely as the 5/2th power o...If the gravitational force were to vary inversely-as mth power of the distance, then the time period of a planet in circ...A geostationary satellite is orbiting the earth at a height of 6R from the earth′s surface (R is the earth′s...Gravitational potential difference between a point on surface of planet and another point 10 m above is 4 J/kg. Consider...