SHMEasy
Question
The displacement of the particle from its mean position (in metre) varies with time (in second) according to the equation y = 0.2 sin (10 πt + 1.5 π) cos (10 πt + 1.5π)
The motion of the particle is :-
The motion of the particle is :-
Options
A.Along a circular path
B.Simple harmonic motion with time period 0.1 s
C.Not simple harmonic motion
D.Simple harmonic motion with time period 0.2 is
Solution
y = 0.2 sin(10πt + 1.5π)cos(10πt + 1.5π)
y = 0.1[2sin(10πt + 1.5π)cos(10πt + 1.5π)]
y = 0.1sin(20πt + 3π) [sin2A = 2sinAcosA]
then T =
= 0.1sec
y = 0.1[2sin(10πt + 1.5π)cos(10πt + 1.5π)]
y = 0.1sin(20πt + 3π) [sin2A = 2sinAcosA]
then T =
= 0.1secCreate a free account to view solution
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