Work, Power and EnergyHard
Question
A gas at pressure 6 × 105 N/m2 and volume 1m3 and its pressure falls to 4 × 105 N/m2. When its volume is 3m3. Given that the indicator diagram is a straight line, work done by the system is :-
Options
A.6 × 105 J
B.3 × 105 J
C.4 × 105 J
D.10 × 105 J
Solution
W = 
× [6 × 105 + 4 × 105] × 2
W = 10 × 105 N/m2
× [6 × 105 + 4 × 105] × 2W = 10 × 105 N/m2
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