Differential EquationHard

Question

The order of the differential equations whose general solution is given by y = (c1 + c2) cos(x + c3) - c4ex+c5 where c1, c2, c3, c4, c5, are arbitrary constants, is

Options

A.5
B.4
C.3
D.2

Solution

Given, y = (c1 + c2) cos (x + c2) - c4ex + c5       .....(i)
⇒     y = (c1 + c2) cos (x + c2) - c4ex . ec5
Now, let c1 + c2 = A,c3 = B, c4ec5 = c
⇒     y = Acos(x + B) - cex     .....(ii)
On differentiating w. r. t. x, we get
      - A sin (A + B) - cex     .....(iii)
Again differentiating w. r. t. x, we get
        - A cos (x + B) - cex     .....(iv)
⇒     - y - 2cex     .....(v)
⇒     + y = - 2cex
Again differentiating w. r. t. x, we get
        - 2cex     .....(vi)
⇒           [from Eq. (v)]
Which is a differential equation of order 3.
is :
or we can write this equation as
y = (k1cos (x + k2) - k3ex    
so there are three arbitrary constant so the general solution will be of third degree.

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