Cell: The Unit of LifeEasy
Question
If in a cell water potential is -30 bar and osmotic potential is -72 bar then what is the value of the turgidity developed in the form of TP in the cell?
Options
A.102 bar
B.-102 bar
C.-42 bar
D.42 bar
Solution
ΨW = ΨS + ΨP [NCERT (E), (H) Pg. # 180]
Water potential (ΨW) = - 30 bar
Osmotic potential (ΨS) = - 72 bar ΨP = ΨW - ΨS
ΨP = - 30 - (-72) = - 30 + 72 = 42 bar
ΨP = TP s o TP = 42 bar
Water potential (ΨW) = - 30 bar
Osmotic potential (ΨS) = - 72 bar ΨP = ΨW - ΨS
ΨP = - 30 - (-72) = - 30 + 72 = 42 bar
ΨP = TP s o TP = 42 bar
Create a free account to view solution
View Solution FreeMore Cell: The Unit of Life Questions
Engine of the cell is...Names of Schleiden and Schwann are associated with...Which of the following lack cell wall...In higher vertebrates, the immune system can distinguish self - cells and non - self. If this property is lostdue to gen...Which one of the following also acts as a catalyst in a bacterial cell ?...