Application of DerivativeHard

Question

The maximum value of (cos α1).(cos α2) ...... (cos αn) under the restrictions 0 ≤ α1, α2, ...., αn and (cot α1).(cotα2)....(cotαn) = 1 is

Options

A.
B.
C.
D.1

Solution

Given, cot α1. cot α2 .... cot αn = 1
⇒    
⇒     Let cos α1.cos α2.cos α3 .... cos αn = k     .....(i)
and     sin α1. sin α2. sin α3 ....sin αn = k     .....(ii)
      Again, multiply Eqs (i) and (ii), we get
      (cos α1 . cos α2. cos α3 ... cos αn) × (sin α1. sin α2. sin α3 ....sin αn) = k2
      k2 (2 sin α1 cos α1) (2sin α2 cos α2)...(2sin αn cos αn)
⇒     k2 = (sin 2 α1) (sin 2α2) ...(sin 2αn)
      ≤ sin 2 αi ≤ 1 for all 1 ≤ i < n
⇒     k ≤

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