Geometrical OpticsHard
Question
The length of astronomical telescope is 15 cm and has magnifying power 4 for normal adjustment. Focal length of the lenses are :-
Options
A.3 cm, 12 cm
B.2 cm, 12 cm
C.3 cm 15 cm
D.4 cm, 11 cm
Solution
L = f0 + fe and |MP| = 
⇒ 15 = f0 + fe & 4 =
⇒ fe = 3 cm and f0 = 12 cm
⇒ 15 = f0 + fe & 4 =
⇒ fe = 3 cm and f0 = 12 cm
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