Physics miscellaneousHard
Question
Ratio of the ranges of the bullets fired from a gun at angle θ, 2θ & 4θ is found in the ratio x : 2 : 2, then the value of x will be (Assume same speed of bullets) :-
Options
A.1
B.2
C.√3
D.2/ √3
Solution
2θ + 4θ = 90° ⇒ 6θ = 90o ⇒ θ = 15o
At angle 2θ & 4θ : R =
at angle θ : R =
so, x = 
At angle 2θ & 4θ : R =
at angle θ : R =
so, x = Create a free account to view solution
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