Photoelectric EffectEasy
Question
The increase in the energy of an electron for changing its de-Broglie wavelength from 1 (Ao) to 0.5 (Ao) will be-
Options
A.1.5 keV
B.0.45 keV
C.0.25 keV
D.100 eV
Solution
As V1 = 
so E1 = 150 eV
V2 =
so E2 = 600 eV
⇒ E2 - E1 = 450 eV = 0.45 keV
so E1 = 150 eVV2 =
so E2 = 600 eV⇒ E2 - E1 = 450 eV = 0.45 keV
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