FunctionHard

Question

Let g(x) = 1 + x -[x] and f(x) = , then for all x, f [g(x)] is equal to

Options

A.x
B.1
C.f(x)
D.g(x)

Solution

g(x) = 1 + x -[x] is greater than 1, since x -[x] > 0
f[g(x)] = 1, since f (x) = 1 for all x > 0
Therefore, (b) is the answer.

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