Work, Power and EnergyHard
Question
A particle of mass m is in a one dimensional potential field and its potential energy is given by the following equation U(x) = Uo(1 - cos αx)where Uo and α are constants. The period of the particle for small oscillations near the equilibrium will be-
Options
A.
B.
C.
D.
Solution
U(x) = U0(1 - cosαx)
F = -
= - U0α[sin α] ≈ - U0α2x
Therefore mω2 = U0α2 ⇒ ω =
⇒ T =
F = -
Therefore mω2 = U0α2 ⇒ ω =
⇒ T =
Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
An ideal gas heat engine operates in Carnot cycle between 227oC and 127oC. It absorbs 6 × 104 cals of heat at highe...A uniform chain of length L and mass M is lying on a smooth table and of its length is hanging down over the edge of the...The kinetic energy of an electron gets tripled, then the de Broglie wavelength associated with it will be 1/n times, whe...Identify the pair whose dimensions are equal...An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the ran...