Work, Power and EnergyHard
Question
An object of mass 5 kg falls from rest through a vertical distance of 20 m and reaches ground with a velocity of 10 m/s. The work done by air resistance is (g = 9.8 m/s2)
Options
A.+730 J
B.-730 J
C.+980 J
D.-930 J
Solution
WC + WnC + Wext = ᐃK
mgh + War + 0 =
mv2 - 0
War =
× 5(10)2 - 5 × 9.8 × 20
= 250 - 980 = - 730 J
mgh + War + 0 =
War =
= 250 - 980 = - 730 J
Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
Two similar springs P and Q have spring constants KP and KQ, such that KP > KQ. The are stretched, first by the same ...Two pith balls carrying equal charges are suspended from a common point by strings of equal length, the equilibrium sepa...A collision is said to be perfectly inelastic when :-...The velocity of a particle of mass of 1 kg changes from 2 m/s north to 2 m/s east in 2 sec. The change in momentum of th...A heavy body moving with a velocity 20 ms-1 and another small object at rest undergo an elastic collision. The latter wi...