CircleHard
Question
The circle x2 + y2 + 2gx + 2fy + c = 0 bisects the circumference of the circle x2 + y2 + 2ax + 2by + d = 0, then -
Options
A.2a (g − a) + 2b (f − b) = c − d
B.2a (g + a) + 2b (f + b) = c + d
C.2g (g − a) + 2f (f − b) = d − c
D.2g (g + a) + 2f (f + b) = c + d
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