CircleHard

Question

The equation of the normal to the circle x2 + y2 − 8x − 2y + 12 = 0 at the points whose ordinate is −1, will be-

Options

A.2x − y − 7 = 0, 2x + y − 9 = 0
B.2x + y − 7 = 0, 2x + y + 9 = 0
C.2x + y + 7 = 0, 2x + y + 9 = 0
D.2x − y + 7 = 0, 2x − y + 9 = 0

Solution

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