CircleHard
Question
The equation of circle which touches the axes of coordinates and the line 
= 1 and whose centre lies in the first quadrant is x2 + y2 − 2cx − 2cy + c2 = 0, where c is-
= 1 and whose centre lies in the first quadrant is x2 + y2 − 2cx − 2cy + c2 = 0, where c is-Options
A.2
B.0
C.3
D.6
More Circle Questions
The sum of the radii of inscribed and circumscribed circles for an n sided regular polygon of side a, is...The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle having area as 154 sq units. Then the equation of the ci...The equation of the circle which touches both the axes and the line + = 1 and lies in the first quadrant is (x _ c)2 + (...x - 2y + 4 = 0 is a common tangent to y2 = 4x & = 1. Then the value of b and the other common tangent are given by -...The centres of the circles x2 + y2 _ 6x _ 8y _ 7 = 0 and x2 + y2 _ 4x _ 10y _ 3 = 0 are the ends of the diameter of the ...