CircleEasy
Question
A circle touches both the axes and its centre lies in the fourth quadrant. If its radius is 1 then its equation will be -
Options
A.x2 + y2 − 2x + 2y + 1 = 0
B.x2 + y2 + 2x − 2y − 1 = 0
C.x2 + y2 − 2x − 2y + 1 = 0
D.x2 + y2 + 2x − 2y + 1 = 0
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