Progression (Sequence and Series)Hard
Question
Let Tr be the r th term of an AP, for r = 1, 2, 3....... if for some positive integers m, n we have Tm =
and Tm =
, then Tm equals
and Tm =
, then Tm equalsOptions
A.

B.

C.1
D.0
Solution
Let Tm = a + (m - 1)d =
.....(i)
and Tm = a + (n - 1)d =
.....(ii)
On subtracting Eq. (ii) form Eq. (i), we get
(m - n)d =
⇒ d =
Again, Tm = a + (mn - 1)d
= a + (mn - n + n - 1)d
= a + (n - 1)d + (mn - n)d
Tn + n(m - 1)
= 1
.....(i)and Tm = a + (n - 1)d =
.....(ii)On subtracting Eq. (ii) form Eq. (i), we get
(m - n)d =
⇒ d =
Again, Tm = a + (mn - 1)d
= a + (mn - n + n - 1)d
= a + (n - 1)d + (mn - n)d
Tn + n(m - 1)
= 1Create a free account to view solution
View Solution FreeMore Progression (Sequence and Series) Questions
The 19th term from the end of the series 2 + 6 + 10 + ....+ 86 is -...If sum of A.M. and H.M. between two positive numbers is 25 and their GM is 12, then sum of numbers is-...Three numbers a,b, 12 are in G.P. and a, b,9 are in A.P., then a and b are -...Let $\displaystyle\sum_{k=1}^{n} a_k = \alpha n^2 + \beta n$. If $a_{10} = 59$ and $a_6 = 7a_1$, then $\alpha + \beta$ i...The sum of n terms of the series + ......... is :-...