Quadratic EquationMedium
Question
For the equation 3x2 + px + 3 = 0, p > 0, if one of the root is square ot the other, then p is equal to
Options
A.1/ 3
B.1
C.3
D.2/3
Solution
Let a,a2 be the roots of 3x2 + px + 3 = 0
Now, S = a + a2 = - p / 3
P = a3 = 1
⇒ a = 1, ω, ω2
Now, a + a2 = p / 3
⇒ ω + ω2 = - p /3
⇒ - 1 = - p/3
⇒ P = 3
Now, S = a + a2 = - p / 3
P = a3 = 1
⇒ a = 1, ω, ω2
Now, a + a2 = p / 3
⇒ ω + ω2 = - p /3
⇒ - 1 = - p/3
⇒ P = 3
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