Quadratic EquationHard
Question
For the equation 3x2 + px + 3 = 0, p > 0, if one of the root is square ot the other, then p is equal to
Options
A.1/ 3
B.1
C.3
D.2/3
Solution
Let a,a2 be the roots of 3x2 + px + 3 = 0
Now, S = a + a2 = - p / 3
P = a3 = 1
⇒ a = 1, ω, ω2
Now, a + a2 = p / 3
⇒ ω + ω2 = - p /3
⇒ - 1 = - p/3
⇒ P = 3
Now, S = a + a2 = - p / 3
P = a3 = 1
⇒ a = 1, ω, ω2
Now, a + a2 = p / 3
⇒ ω + ω2 = - p /3
⇒ - 1 = - p/3
⇒ P = 3
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
The HM of the roots of the equation x2 − 8x + 4 = 0 is -...If α, β are roots of the equation x2− mx + n = 0, then value of (1 + α + α2) (1+ β + ^...Roots of the equation are-...If α, β are the roots of ax2 + bx + c = 0 and α + h, β + h are the roots of px2 + qx + r = 0, then h...Let α, β be the roots of the equation (x - a)(x - b) = c, c ≠ 0 Then the roots of the equation (x - ^...