Complex NumbersHard
Question
The value of sum
(in + in + 1), where i = √-1 equals
(in + in + 1), where i = √-1 equalsOptions
A.i
B.i - 1
C.-i
D.0
Solution
(in + in + 1) =
in(1 + i) = (1 + i)
in = (1 + i) = (1+ i2 + i3 + ......+ i13) = (1 + i)

= (1+ i)i = -1+ i
Alternate Solution
Since, sum of any four consecutive powers of iota is zero.
∴
(in + in+1) = (i + i2 + ...... + i13)+ (i2 + i3+ .......+i14) = i + i13 + ......+ i14
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