Complex NumbersMedium
Question
If ω(≠ 1) is a cube root of unity and (1 + ω)7 = A + Bω, then A and B are respectively
Options
A.0 , 1
B.1, 1
C.1, 0
D.- 1, 1
Solution
(1 + ω)7 = (1 + ω)(1 + ω)6
= (1 + ω)(-ω2)6
= 1 + ω
⇒ A + B ω = 1 + ω ⇒ A = 1, B = 1
= (1 + ω)(-ω2)6
= 1 + ω
⇒ A + B ω = 1 + ω ⇒ A = 1, B = 1
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