Trigonometric EquationEasy
Question
In ᐃABC, tan C < 0 then
Options
A.tan A. tan B > 1
B.tan A + tan B + tan C < 0
C.tan A + tan B + tanc C > 0
D.None
Solution
In ᐃABC, tan C < 0 then C is obtuse angle
So A and B are acute
tan A > 0 tan B > 0
So tan A + tn B > 0 tan A . tan B > 0
For triangle
[tan A + tan B + tan C = tan A . tan B . tan C]
tan A . tan B > 0
tan C < 0
So tan A + tan B + tan C < 0
So A and B are acute
tan A > 0 tan B > 0
So tan A + tn B > 0 tan A . tan B > 0
For triangle
[tan A + tan B + tan C = tan A . tan B . tan C]
tan A . tan B > 0
tan C < 0
So tan A + tan B + tan C < 0
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