Trigonometric EquationHard
Question
A curve passes through (2, 0) and the slope of tangent at a point P(x, y) is equal to 
. Then equation of the curve is
. Then equation of the curve isOptions
A.y = x2 + 2x
B.y = x2 - 2x
C.y = 2x2 - x
D.None of these
Solution
= (x + 1) + 
Putting x + 1 = X, y - 3 = Y,
the equation becomes
. Y = X [L.D.E.]I.F. = e∫(-1/ X)dX = e-log x =
∴ the solution is
Y.
= c + ∫ X 
dx = c + Xor
= c + x + 1x = 2, y = 0 ⇒
= c + 2 + 1⇒ c = - 4
∴ the quation of the curve is
= x - 3 or y = x2 - 2x.Create a free account to view solution
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