Permutation and CombinationHard
Question
The number of numbers can be formed by taking any 2 digits from digits 6,7,8,9 and 3 digits from 1,2,3,4,5 is -
Options
A.5C3 × 4C2 × 3! × 2!
B.5P3 × 4P2 × 5!
C.5C3 × 4C2 × 5!
D.5C3 × 4C2 ×
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