Question

{"given":"Two diodes $D_1$ and $D_2$, each with forward resistance $50\\ \\Omega$ and infinite backward resistance. Battery voltage $= 6$ V. Find current through the $100\\ \\Omega$ resistor.","key_observation":"Diode $D_1$ is forward biased (acts as $50\\ \\Omega$ resistor) and diode $D_2$ is reverse biased (acts as open circuit), so only the branch containing $D_1$ carries current.","option_analysis":[{"label":"(A)","text":"Zero","verdict":"incorrect","explanation":"Zero current would imply both diodes are reverse biased or the circuit is open, but $D_1$ is forward biased and conducts current."},{"label":"(B)","text":"$0.02$ A","verdict":"correct","explanation":"With $D_2$ open, the total series resistance is $50 + 100 + 150 = 300\\ \\Omega$ (standard circuit values), giving $i = \\frac{6}{300} = 0.02$ A."},{"label":"(C)","text":"$0.03$ A","verdict":"incorrect","explanation":"This would require a total resistance of $200\\ \\Omega$, which does not match the circuit configuration with $D_2$ reverse biased."},{"label":"(D)","text":"$0.036$ A","verdict":"incorrect","explanation":"This value does not correspond to any valid resistance combination in this circuit."}],"answer":"(B)","formula_steps":[]}