Binomial TheoremHard
Question
If (1 + x)n = C0 + C1 x + C2 x2 + ....+ Cn .xn then the value of C0Cn + C1Cn-1 + C2 Cn-2 + ....+ CnC0 is -
Options
A.1
B.
C.
D.(2n)2
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