Binomial TheoremEasy
Question
If (1 + x)n = C0 + C1 x + C2 x2 + ...+ Cnxn, then the value of C0 + 2C1 + 3C2 + ....+(n +1)Cn is -
Options
A.2n (n + 1)
B.2n-1 (n + 1)
C.2n-1 (n + 2)
D.2n (n + 2)
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