ElectroMagnetic InductionHard
Question
A coil of wire having finite inductance and resistance has conducting ring placed co-axially with in it. The coil is connected to a battery at time t = 0, so that a time dependent current I1(t) start flowing through the coil. If I2(t) is the current induced in the ring and B(t) is the magnetic field at the axis of the coil due to I1(t) then as a function of time (t > 0), the product I2(t)B(t)
Options
A.increases with time
B.decreases with time
C.does not very with time
D.passes through a maximum
Solution
The equation of I1(t), I2(t) and B(t) will take following forms :
I1(t) = K1(1 - e-k2t) → current growth in L-R circuit
B(t) = K3(1 - e-k2t) → B(t) ∝ I1(t)
I2(t) = K4e-k2t)
Therefore, the product I2(t) B(t) = K5e-k2t(1 - e-k2t).
The value of this product is zero at t = 0 and t = ∞ Therefore, the product will pass through a maximum value. The corresponding graphs will be as follows :
Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A coil having 500 square loops each of side 10 cm is placed normal to a magnetic field which increased at a rate of 1.0 ...In order to avoid eddy currents in the core of a transformer :-...A conducting rod of length is moved at constant velocity ′v0′ on two parallel, conducting, smooth, fixed rai...A coil has an inductance of 0.7 henry and is joined in series with a resistance of 220Ω. When the alternating emf o...Side of a square coil is 4 cm. A magnetic field normal to plane of coil is changing at a rate of 0.4 tesla/sec. If resis...