Progression (Sequence and Series)Easy
Question
-A man arrange to pay off a loan of Rs.3600 by 40 annual instalments which are in AP. When 30 of the instalments are paid, he dies leaving one third of the loan amount unpaid. The value of the 8th instalment is :-
Options
A.Rs. 35
B.Rs. 50
C.Rs. 65
D.Rs. 80
Solution
Let the first instalment be a and common difference of AP be d.
Given, 3600 = sum of 40 terms
=
[2a + (40 - 1)d]
⇒ 2a + 39d = 180 ....(i)
After 30 instalments one-third of the loan is unpaid.
Now
= 1200 is unpaid and 2400 is paid
So, 2400 =
[2a + (30 - 1)d]
⇒ 2a + 29d = 160 .....(ii)
Solving eq. (i) & (ii) a = 51, d = 2
So 8th instalment = a + (8 - 1) d = 65
Given, 3600 = sum of 40 terms
=
[2a + (40 - 1)d]⇒ 2a + 39d = 180 ....(i)
After 30 instalments one-third of the loan is unpaid.
Now
= 1200 is unpaid and 2400 is paidSo, 2400 =
[2a + (30 - 1)d]⇒ 2a + 29d = 160 .....(ii)
Solving eq. (i) & (ii) a = 51, d = 2
So 8th instalment = a + (8 - 1) d = 65
Create a free account to view solution
View Solution FreeMore Progression (Sequence and Series) Questions
If third and seventh terms of a GP are 15 and 135 respectively, then its fifth term will be-...The sum to first ' $n$ ' terms of the series $(n \geq 3)1^{2} + 2 \cdot 2^{2} + 3^{2} + 2 \cdot 4^{2} + 5^{2} + 2 \cdot ...In an arranged series of n observations (n being an odd number) , the median is the value of -...If S1, S2, S3 are the sums of first n natural numbers, their squares, their cubes respectively, then is equal to -...If (m + 2)th term of an A.P. is ( m+2)2 − m2, then its common difference is-...