Magnetic field due to currentHard
Question
A particle of charge +q and mass m moving under the influence of a uniform electric field E
and uniform magnetic field B
follows a trajectory from P to Q as shown in figure. The velocities at P and Q are 
and 
. Which of the following statement(s) is /are correct ?
and uniform magnetic field B follows a trajectory from P to Q as shown in figure. The velocities at P and Q are and . Which of the following statement(s) is /are correct ? Options
A.
B.Rate of work done by the electric field at P is 
C.Rate of work done by the electric field at P is zero
D.Rate of work done by the electric field at Q is zero
Solution
Magnetic force does not do work. From work energy theorem :
WFe = ᐃ KE or (qE)(2a) =
m[4v2 - v2]
or E =
∴ Correct option is (a).
At P, rate or work done by electric field
=
= (qE) (v) cos0o
Therefore, option (b) is also correct.
Rate of work done at Q :
of electric field =
= (qE) (v) cos 90o = 0
and of magnetic field is always zero. Therefor, option (d) is also correct.
WFe = ᐃ KE or (qE)(2a) =
m[4v2 - v2]or E =
∴ Correct option is (a).
At P, rate or work done by electric field
=
= (qE) (v) cos0oTherefore, option (b) is also correct.
Rate of work done at Q :
of electric field =
= (qE) (v) cos 90o = 0and of magnetic field is always zero. Therefor, option (d) is also correct.
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