Magnetic field due to currentEasy
Question
wo particles A and B of masses mA and mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to the plane. The speed of the particles are vA and vB respectively and the trajectories are as shown in the figure. Then
Options
A.mAvA > mBvB
B.mAvA < mBvB
C.mA < mB and vA < vB
D.mA = mB and vA = vB
Solution
Radius of the circle = 
or radius ∝ mv if B and q are same
(Radius)A > (Radius)B
∴ mAvA > mBvB
or radius ∝ mv if B and q are same
(Radius)A > (Radius)B
∴ mAvA > mBvB
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