Magnetic field due to currentHard
Question
A particle of charge q and mass m moves in a circular orbit of radius r with angular speed ω. The ratio of the magnitude of its magetic moment to that of its angular momentum depend on
Options
A.ω and q
B.ω, q and m
C.q and m
D.ω and m
Solution
Ratio of magnetic moment and angular momentum is given by
Which is a function of q and m only. This can be derived as follows
M = iA = (qf).(πr2)
= (q)
and L = Iω = (mr2)
∴
Which is a function of q and m only. This can be derived as follows
M = iA = (qf).(πr2)
= (q)
and L = Iω = (mr2)
∴
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
Two very long, straight, parallel wires carry currents I and -I respectively. The distance between the wires is d. At a ...The electric and the magnetic field, associated with an e.m. wave propagating along the +z axis, can be represented by :...Two tangent galvanometer, coil of same radius connected in series. The current flowing produces deflections of 60o and 4...An electron (mass = 9.1 × 10-31; charge = - 1.6 × 10-19 C) experiences no deflection if subjected to an electr...A particle having charge q enters a region of uniform magnetic field (directed inwards) and is deflected a distance x af...