Magnetic field due to currentHard
Question
A particle of charge q and mass m moves in a circular orbit of radius r with angular speed ω. The ratio of the magnitude of its magetic moment to that of its angular momentum depend on
Options
A.ω and q
B.ω, q and m
C.q and m
D.ω and m
Solution
Ratio of magnetic moment and angular momentum is given by

Which is a function of q and m only. This can be derived as follows
M = iA = (qf).(πr2)
= (q)
and L = Iω = (mr2)
∴

Which is a function of q and m only. This can be derived as follows
M = iA = (qf).(πr2)
= (q)

and L = Iω = (mr2)
∴
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
Weber-ampere per meter is equivalent to :-...The best material for the core of a transformer is...Two long thin parallel wires are placed at a distance (r) from each other carrying equal current I in opposite direction...A long solenoid has 1000 turns. When a current of 4A flows through it the magnetic flux linked with each turn of the sol...A conductor of length l and mass m is placed along the east-west line on a table. Suddenly a certain amount of charge is...