Chemical EquilibriumEasy
Question
Calculate equilibrium constant (approx) at 25oC for the cell reaction
Fe(s) + CuSO4 ⇋ FeSO4 + Cu(s)
Given : EoFe/Fe+2 = + 0.453 volt ;
EoCu/Cu+2 = - 0.3435 volt
Fe(s) + CuSO4 ⇋ FeSO4 + Cu(s)
Given : EoFe/Fe+2 = + 0.453 volt ;
EoCu/Cu+2 = - 0.3435 volt
Options
A.1.0 × 1025
B.1.0 × 1020
C.1.0 × 1027
D.1.0 × 1022
Solution
Eocell = (EoRP)cathode - (EoRP)anode
Eocell = 0.3435 - (-0.453)
Eocell = 0.3435 + 0.453
= 0.7965 volt
Eocell =
log Keq
log Keq =
= 27 ⇒ Keq = 1027
Eocell = 0.3435 - (-0.453)
Eocell = 0.3435 + 0.453
= 0.7965 volt
Eocell =
log Keqlog Keq =
= 27 ⇒ Keq = 1027Create a free account to view solution
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