Math miscellaneousHard
Question
If (-2, 6) is the image of the point (4, 2) with respect to the line L = 0, then L =
Options
A.3x - 2y + 5
B.3x - 2y + 10
C.2x + 3y - 5
D.6x - 4y - 7
Solution
Clearly, L = 0 is the perpendicular bisector of the segment joining (-2, 6) and (4, 2). The equation of which is
y - 4 =
(x - 1) ⇒ 3x - 2y + 5 = 0
∴ L = 3x - 2y + 5
y - 4 =
(x - 1) ⇒ 3x - 2y + 5 = 0∴ L = 3x - 2y + 5
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